This is an easy one, but some people don’t know it: if you need the last two digits of a year, say 2007, it’s very easy to get, without converting to a string and getting the last two characters:
int lastTwo = year % 100;
Now that you know, it’s obvious, right?
And if you want the last three digits? number % 1000. In general:
int lastN = number % (pow(10, digitsRequired));
What about first N digits? similarly easy:
int firstTwo = number / 100;
int firstN = number / pow(10,digitsRequired);
Now you know, and knowing if half the battle.
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int lastTwo = year % 100;
this doesn’t give the last two digits. For 2007, i want 07 but the operation will give me 7.
nec, to get the zero, in the formatted output you will have to pad it. In C, it would be:
printf(“%02d”, lastTwo);
Suppose you have 2027 %100. Then the answer is, correctly, 27.
yeah, i know. just pointing out that it’s not a single expression as i see that post as a tutorial.